Calculating point/vertices of triangle

[lynchtkd]

Hi all,

I an wondering if anyone can help me with the following problem. I have a line segment |AB| and another segment |BC|. They are both the same length and I know points A and B and the angle ABC. Is there any way I can calculate point C.

Cheers

[silent_swordsman]

two ways
- 1st, 180 degree substrsact point A and point B
- 2nd, using the theorem of thigonometry sin [B](length AB)

[HallsofIvy]

Hi all,

I an wondering if anyone can help me with the following problem. I have a line segment |AB| and another segment |BC|. They are both the same length and I know points A and B and the angle ABC. Is there any way I can calculate point C.

Cheers
That's an iscosceles triangle so angle BAC and angle BCA both have measure (1/2)(180 - ABC) in degrees. You can also find the length of AC using the cosine law: AC^2= BC^2+ AB^2- 2(BC)(AB)cos(ABC). That is enough information to find coordinates of C given coordinates of A and B.