lemon
11-07-2009, 04:46 PM
(4x+a)^3=px^3+qx^2+108x-27
I have expanded this correctly using pascal's triangle.
64x^3+48ax^2+12a^2x+a^3=px^3+qx^2+108x-27
But, need to find values of a, p and q.
For p=16x^2(4x-3)a^2(12x+a)-27(4x+a)+q / x^3
When asked to find the values of a, p and q, is this a correct answer for q, or do I have to now substitute this whole value into original equation to find other values?
for q=16x^2(4x+3)-a^2(12x+a)-27(4x-1)-p / x^3
Not sure about a, as there is an a^2 plus an a.
Help please.
I have expanded this correctly using pascal's triangle.
64x^3+48ax^2+12a^2x+a^3=px^3+qx^2+108x-27
But, need to find values of a, p and q.
For p=16x^2(4x-3)a^2(12x+a)-27(4x+a)+q / x^3
When asked to find the values of a, p and q, is this a correct answer for q, or do I have to now substitute this whole value into original equation to find other values?
for q=16x^2(4x+3)-a^2(12x+a)-27(4x-1)-p / x^3
Not sure about a, as there is an a^2 plus an a.
Help please.