PDA

View Full Version : Gravitational force mechanism for quantum field theory?


T.E. Jones
01-12-2006, 12:52 PM
http://members.lycos.co.uk/nigelbryancook/Image31.gif

http://members.lycos.co.uk/nigelbryancook/Image36.gif

"1. Feynman shows that forces arise from the exchange of gauge bosons (coming from distances at light speed, hence coming from times in the past).

"2. The big bang mass has a speed, in the spacetime which we see, from 0 toward speed of light c with times past of 0 toward 15 billion years (or distances of 0 to 15 billion light-years), giving outward force by Newton’s 2nd empirical law: F = ma = m.dv/dt = mc/(age of universe).

"3. Newton’s 3rd law gives equal inward force, carried by gauge bosons, which shielded by mass, proves gravity and electromagnetism to within 1.65% - http://feynman137.tripod.com/

"SIMPLE PROOF: There is strong evidence from electromagnetic theory that every fundamental particle has black-hole cross-sectional shield area for the fluid analogy of general relativity.

"The effective shielding radius of a black hole of mass M is equal to 2GM/c2. A shield, like the planet earth, is composed of very small, sub-atomic particles. The very small shielding area per particle means that there will be an insignificant chance of the fundamental particles within the earth ‘overlapping’ one another by being directly behind each other.

"The total shield area is therefore directly proportional to the total mass: the total shield area is equal to the area of shielding by 1 fundamental particle, multiplied by the total number of particles. (Newton showed that a spherically symmetrical arrangement of masses, say in the earth, by the inverse-square gravity law is similar to the gravity from the same mass located at the centre, because the mass within a shell depends on its area and the square of its radius.) The earth’s mass in the standard model is due to particles associated with up and down quarks: the Higgs field.

"From the illustration above, the total outward force of the big bang,

"(total outward force) = ma = (mass of universe).(Hubble acceleration, a = Hc, see detailed discussion and proof further on below),

"while the gravity force is the shielded inward reaction (by Newton’s 3rd law the outward force has an equal and opposite reaction):

"F = (total outward force).(cross-sectional area of shield projected to radius R) / (total spherical area with radius R).

"The cross-sectional area of shield projected to radius R is equal to the area of the fundamental particle (p multiplied by the square of the radius of the black hole of similar mass), multiplied by the (R/r)^2 which is the inverse-square law for the geometry of the implosion. ..." - http://feynman137.tripod.com/

http://members.lycos.co.uk/nigelbryancook/Image37.gif

Above: the contraction effect in general relativity, whereby the earth's radius is compressed by (1/3)MG/c^2 or 1.5 mm, has the same physical cause as gravity.