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View Full Version : "Snap" of a Whip:Formula for cause


drjustian
05-12-2007, 10:49 AM
There is a 'snap' in the air when a whip is used. The energy created at the larger dimension of the handle does not increase along the whip to the 'snap' end of the whip (otherwise we would have some potential for perpertual motion). So the resulting magnitude of energy at the end of the whip (with the smaller dimension ) than the handle is the same, or lesser than, the magnitude of energy at the handle end. What is the formula for describing the magnitude of the energy force at each point along the whip from the handle to the small end of the whip? The relevant factors, I believe, may include the diameter of the handle, the diameter of the final 'snap' point, the initial energy used to begin the energy travel along the whip. The points along the whip to be measured or explained are arbitary (one cm, one inch, whatever) apart. The initial energy is also arbitrary though we know (dont' we?) that the more energy the louder the 'snap'. However, regardless of the intial energy at the handle, and regardless of the distance between arbitary points along the whip, What formula can be used to establish energy measurment that can be transformed to any inertial system and used in any inertial system. Understand that the 'effect' of energy may be different at each of the arbitrary points even though the magnitude of energy may be the same (or decreasing) at all points along the whip.

HallsofIvy
09-24-2007, 01:23 AM
How many times are you going to post this same question? There simply isn't enough information to answer it. you would have to give us a formula for the speed of each part of the whip. Whips can be "snapped" in different ways only very specific ways will result in a "crack". It's not that easy to crack a whip!

Epsilon=One
09-24-2007, 01:43 AM
How many times are you going to post this same question? There simply isn't enough information to answeCurrently, all posts, and edits, from mid-May, 2007 to the present have been lost on the forum.

Today, you have been answering posts from May.

See: Astro's Announcement re: Server Crash (physicsmathforums.com/showthread.php?t=2682).