small calculus question

[Dionysus22]

Just looking for a solution for a small differentiation question:

Find the (dy/dx) of;

x = (1+Sint)/Cost, y = (1+Cost)/Sint........where 0 < t < pi

I know that dy/dx = (dy/dt) x (dt/dx) but I'm getting a far too long winded answer. All help is appreciated.

Thanks,
-D22

[HallsofIvy]

x = (1+Sint)/Cost, y = (1+Cost)/Sint

dx/dt= (Cos^2 t- (-Sint)(1+ Sint)/Cos^2 t
= (1+ Sin t)/Cos^2 t
dy/dt= (-Sin^2 t- Cos t(1+ Cos t))/Sin^2 t
= (-1- Cos(t))/Sin^2 t

So dy/dx= -(Tan^2 t)(1+ Cos t)/(1+ Sin t)

Don't see anything "long winded" about that!

[Dionysus22]

I did when I attempted it...Got it completely wrong.
Thanks...